Online Angle between two straight lines Tutor & Homework Help

Solution Angle between two straight lines Parallel, Perpendicular Tutoring Online, Tutor Help
ANGLES BETWEEN TWO STRAIGHT LINES:
THEOREM 1:
To find the angle between two given straight lines.
Solution:
Let the two straight lines be AT1 and AT2 which meet at x-axis at T1 and T2 points respectively.
Let the equations of the two lines AT1 and AT2 be
y = m1x + c1 and y2 = m2x + c2
(1)
Hence tan AT1X = m1 and tan AT2X = m2
Now ∠T1AT2 = ∠AT1X - ∠AT2X
Hence tan T1AT2 = tan [AT1X - AT2X]
Hence the required angle = ∠T1AT2
(2)
If equation (2) is a positive quantity then it is the tangent of the acute angle between the
two lines, if (2) is a negative quantity then it is the tangent of the obtuse angle.
Example:
Find the angle between two straight lines y = 6x - 11 and
Solution:
The equation of the first line is y = 6x - 11 which implies m1 = 6.
The equation of the second line is
hence
hence
THEOREM 2:
To find the condition that two straight lines can be parallel.
Two straight lines are parallel when the angle between them is zero and hence the tangent
of this angle is zero. Hence in theorem 1 the equation (2) becomes
m1 = m2 which is the required result.
Example:
Find the equation of a straight line which passes through the point (4, -5) and which is
parallel to the straight line 3x + 4y + 5 = 0.
Solution:
Any straight line which is parallel to 3x + 4y + 5 = 0 will be 3x + 4y + c2 = 0 because m1 = m2.
Now given that this line 3x + 4y + c2 = 0 passes through the point (4, -5) hence we get,
3. 4 + 4. (-5) + c2 = 0 or c2 = 8
Putting the value of c2 = 8 we get 3x + 4y + 8 = 0. (Answer)
THEOREM 3:
To find the condition that two straight lines can be perpendicular.
Let the two straight lines be y = m1x + c1 and y2 = m 2x + c2
If the angle between them is θ then by theorem 1,
(1)
If the two lines are perpendicular then θ = 90 ο
and so tan θ = ∞.
Hence in equation (1)
which is only
possible if the denominator is zero
which is only
possible if the denominator is zero
Therefore the condition of perpendicularity is
1 + m1m2 = 0 or m1m2 = -1.
Hence the straight line y2= m2x + c2 is perpendicular to y = m1x + c1 if
Example:
Find the equation of a straight line which passes through the point (4, -5) and is perpendicular
to the straight line 3x + 4y + 5 = 0.
Solution:
Let the equation of a straight line be y = m1x + c
Now given that this line passes through the point (4, -5) hence it becomes, -5 = 4m1 + c
(1)
Given that the above line is perpendicular to the straight line 3x + 4y + 5 = 0 (2)
From (2) we get
where
where
Then by the condition of perpendicularity m1m2 = -1.
Hence
Or
putting which in eq.
(1) we get,
putting which in eq.
(1) we get,
Hence the required equation will be
Or 4x - 3y = 31 (Answer)
Or 4x - 3y = 31 (Answer)
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